[Event "Philadelphia Open 2015"]
[Site "Philadelphia"]
[Date "2015.04.03"]
[Round "4.3"]
[White "Dreev, Aleksey"]
[Black "Gerzhoy, Leonid"]
[Result "1-0"]
[ECO "D11"]
[WhiteElo "2636"]
[BlackElo "2430"]
[Annotator "Kleinman,M"]
[PlyCount "113"]
[EventDate "2015.04.??"]
[EventRounds "9"]
[EventCountry "USA"]
1. d4 d5 2. c4 c6 3. Nf3 Nf6 4. e3 Bg4 5. Nc3 e6 6. Qb3 Qb6 7. Nh4 Nbd7 8. h3
Bh5 9. g4 Bg6 10. Nxg6 hxg6 11. Bg2 Be7 {Black is extremely solid, but White
collects the stable advantage of the bishop pair.} 12. Bd2 {Developing the
last remaining piece to the best square.} O-O 13. O-O-O Qxb3 14. axb3 {I'm not
sure I understand this follow up, though I have to admit, I'm not familiar
with these types of structures.} Bb4 (14... g5 {with the idea of Re8 followed
by swinging the d7 knight to g6 makes sense.}) 15. g5 Nh5 (15... Ne8) 16. h4 {
Notice how the Black knight on h5 is virtually trapped.} a5 17. Kc2 f5 18. Bf3
Nb6 19. Na4 Nxa4 20. bxa4 dxc4 21. Bc3 {Black is up a pawn, but do to the fact
that his knight is practically useless on h5, White stands slightly better.}
Rad8 22. Ra1 {This is a deep move. White prepares to play Be2, and wants to be
ready for b5 by having his rook on the open a-file.} Rd7 23. Rhd1 Rfd8 24. Be2
b5 25. Bf3 (25. axb5 {was better because the bishop turns out to be useful on
e2} cxb5 26. Bxb4 axb4 27. b3 Rc7 28. bxc4 bxc4 29. Ra4 $16 {The pawns fall})
25... Rd6 26. axb5 cxb5 27. Bxb4 axb4 28. Ra5 Rb8 29. Ra7 Kh7 30. Ra5 Kg8 31.
Rda1 f4 {Solving the problem of the h5 knight.} 32. Ra8 Rxa8 33. Rxa8+ Kh7 34.
Rb8 fxe3 35. fxe3 Ng3 36. Rxb5 Nf5 37. Rxb4 Nxe3+ 38. Kc3 e5 39. d5 Nxd5+ 40.
Bxd5 Rxd5 {While usually rook endgames are drawish, the poor placement of the
Black king makes this position very difficult.} 41. Rxc4 Kg8 42. b4 Kf7 43.
Rc7+ Kf8 44. Ra7 e4 45. Ra5 Rd3+ 46. Kc4 Rh3 47. Re5 Rxh4 48. b5 {The black
king is cut off. White just needs to collect the e pawn, and has a technically
winning position.} e3+ 49. Kd3 Rh1 50. Rxe3 Rc1 51. Kd4 Kf7 52. b6 Rb1 53. Kc5
Rc1+ 54. Kb4 Rc6 55. Kb5 Rc1 56. Rb3 Rc8 57. b7 1-0
